What is the answer to 4= 3/(2-x)+3/(2+x) ?

The answer to 4= 3/(2-x)+3/(2+x) is x=1,x=-1

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4= 3/(2-x)+3/(2+x)

4 = \frac{3}{2 - x} + \frac{3}{2 + x}

x = 1, x = - 1

Solution steps

4 = \frac{3}{2 - x} + \frac{3}{2 + x}

Multiply by LCM

4 (- x + 2) (x + 2) = 3 (x + 2) + 3 (- x + 2)

Solve

4 (- x + 2) (x + 2) = 3 (x + 2) + 3 (- x + 2) : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = 1, x = - 1

18 = \frac{1000}{0.707 h ( 3.5 )}

x, \frac{- 1}{x ^{2}} = 0

- \frac{3}{x} = \frac{11}{3 x} - 5

7 = x - \frac{8}{x}

\frac{277}{x - 277} = 2.1

What is the answer to 4= 3/(2-x)+3/(2+x) ?
The answer to 4= 3/(2-x)+3/(2+x) is x=1,x=-1
Solve for x: 4= 3/(2-x)+3/(2+x)
The solution is x=1,x=-1