What are the solutions to the equation 720=(2x-4)(x) ?

The solutions to the equation 720=(2x-4)(x) are x=20,x=-18

Find the zeros of 720=(2x-4)(x)

The zeros of 720=(2x-4)(x) are x=20,x=-18

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720 = (2 x - 4) (x)

x = 20, x = - 18

Solution steps

720 = (2 x - 4) (x)

Expand

(2 x - 4) (x) : 2 x^{2} - 4 x

720 = 2 x^{2} - 4 x

Switch sides

2 x^{2} - 4 x = 720

Move

720

to the left side

2 x^{2} - 4 x - 720 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 720 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 720) = 76

x_{1, 2} = \frac{- ( - 4 ) \pm 76}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 76}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 76}{2 \cdot 2}

x = \frac{- ( - 4 ) + 76}{2 \cdot 2} : 20

x = \frac{- ( - 4 ) - 76}{2 \cdot 2} : - 18

The solutions to the quadratic equation are:

x = 20, x = - 18

x^{2} - 2 x \leq 15

- 3 + \frac{1}{8}

\frac{x}{x + 2} \geq 3

- 6 + 7 k = 50

\frac{1}{8 ^{3}}

What are the solutions to the equation 720=(2x-4)(x) ?
The solutions to the equation 720=(2x-4)(x) are x=20,x=-18
Find the zeros of 720=(2x-4)(x)
The zeros of 720=(2x-4)(x) are x=20,x=-18