What is the answer to 0=(x^2-2x)/((x-1)^2) ?

The answer to 0=(x^2-2x)/((x-1)^2) is x=2,x=0

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0=(x^2-2x)/((x-1)^2)

0 = \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

x = 2, x = 0

Solution steps

0 = \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = x^{2} - 2 x

Solve

0 = x^{2} - 2 x : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = 0

\frac{4}{h} = \frac{h}{36}

\frac{x}{x - 3} = 1

\frac{1}{x} + \frac{4}{x - 8} = 0

\frac{5}{1 - 3 x} = 2021

\frac{2 x + 8 b + 5 c}{x + b + c} = 5

What is the answer to 0=(x^2-2x)/((x-1)^2) ?
The answer to 0=(x^2-2x)/((x-1)^2) is x=2,x=0
Solve for x: 0=(x^2-2x)/((x-1)^2)
The solution is x=2,x=0