What are the solutions to the equation (x-3)^2-2=-5 ?

The solutions to the equation (x-3)^2-2=-5 are x=sqrt(3)i+3,x=-sqrt(3)i+3

Find the zeros of (x-3)^2-2=-5

The zeros of (x-3)^2-2=-5 are x=sqrt(3)i+3,x=-sqrt(3)i+3

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(x - 3)^{2} - 2 = - 5

x = 3 i + 3, x = - 3 i + 3

Solution steps

(x - 3)^{2} - 2 = - 5

Move

2

to the right side

(x - 3)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 3 : x = 3 i + 3

Solve

x - 3 = - - 3 : x = - 3 i + 3

The solutions to the quadratic equation are:

x = 3 i + 3, x = - 3 i + 3

2 x^{2} - x - 10 > 0

\frac{( x + 3 ) - 3 + 1}{( 2 3 ) x} \leq 0.1

\frac{x - 3}{6} = 2 - \frac{5 ( x + 3 )}{12}

- 7 x > 10

lo g_{2} (\frac{x}{4})

What are the solutions to the equation (x-3)^2-2=-5 ?
The solutions to the equation (x-3)^2-2=-5 are x=sqrt(3)i+3,x=-sqrt(3)i+3
Find the zeros of (x-3)^2-2=-5
The zeros of (x-3)^2-2=-5 are x=sqrt(3)i+3,x=-sqrt(3)i+3