What is the answer to x^{-1}+x-2=0 ?

The answer to x^{-1}+x-2=0 is x=1

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x^{-1}+x-2=0

x^{- 1} + x - 2 = 0

x = 1

Solution steps

x^{- 1} + x - 2 = 0

Refine

\frac{1}{x} + x - 2 = 0

Multiply both sides by

x

1 + x^{2} - 2 x = 0

Solve

1 + x^{2} - 2 x = 0 : x = 1

x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1

\frac{x + 5}{x - 2} = 2

L^{- 1} = [\frac{s}{s ^{2} + 2 s - 3}]

\frac{1}{3} = - \frac{2}{x}

D = 1000000 n^{- 2}

\frac{5 x - 4}{2 x - 1} = 3