What are the solutions to the equation 6x^2+13x=63 ?

The solutions to the equation 6x^2+13x=63 are x= 7/3 ,x=-9/2

Find the zeros of 6x^2+13x=63

The zeros of 6x^2+13x=63 are x= 7/3 ,x=-9/2

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6 x^{2} + 13 x = 63

x = \frac{7}{3}, x = - \frac{9}{2}

Solution steps

6 x^{2} + 13 x = 63

Move

63

to the left side

6 x^{2} + 13 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 ( - 63 )}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 (- 63) = 41

x_{1, 2} = \frac{- 13 \pm 41}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 13 + 41}{2 \cdot 6}, x_{2} = \frac{- 13 - 41}{2 \cdot 6}

x = \frac{- 13 + 41}{2 \cdot 6} : \frac{7}{3}

x = \frac{- 13 - 41}{2 \cdot 6} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{9}{2}

0.391666 = (4.38324) (x - (- 3 \cdot \frac{π}{180}))

∣ x + 1 ∣ = ∣ x + 2 ∣

(x - 1) (x + 1) = 2 (5 x - \frac{10}{12})

- 2.4 (4) + 9.6

\frac{10}{10 - 4}

What are the solutions to the equation 6x^2+13x=63 ?
The solutions to the equation 6x^2+13x=63 are x= 7/3 ,x=-9/2
Find the zeros of 6x^2+13x=63
The zeros of 6x^2+13x=63 are x= 7/3 ,x=-9/2