What is the answer to 1-1/(k^2)=0.89 ?

The answer to 1-1/(k^2)=0.89 is k=(10)/(sqrt(11)),k=-(10)/(sqrt(11))

Solve for k: 1-1/(k^2)=0.89

The solution is k=(10)/(sqrt(11)),k=-(10)/(sqrt(11))

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1 - \frac{1}{k ^{2}} = 0.89

k = \frac{10}{11}, k = - \frac{10}{11}

Decimal Notation

k = 3.01511 \dots, k = - 3.01511 \dots

Solution steps

1 - \frac{1}{k ^{2}} = 0.89

Move

1

to the right side

- \frac{1}{k ^{2}} = - 0.11

Multiply both sides by

k^{2}

- 1 = - 0.11 k^{2}

Solve

- 1 = - 0.11 k^{2} : k = \frac{10}{11}, k = - \frac{10}{11}

k = \frac{10}{11}, k = - \frac{10}{11}

Verify Solutions

Find undefined (singularity) points:

k = 0

Combine undefined points with solutions:

k = \frac{10}{11}, k = - \frac{10}{11}

\frac{16}{14} = \frac{8}{x}

\frac{12}{x} = \frac{22}{66}

\frac{( 2 x - 6 ) ( x - 4 )}{x + 3} = 0

\frac{2 π}{x} = 4 π

\frac{a + 2}{a - 4} = 1

What is the answer to 1-1/(k^2)=0.89 ?
The answer to 1-1/(k^2)=0.89 is k=(10)/(sqrt(11)),k=-(10)/(sqrt(11))
Solve for k: 1-1/(k^2)=0.89
The solution is k=(10)/(sqrt(11)),k=-(10)/(sqrt(11))