What is the answer to 0=1-4/((x+1)^2) ?

The answer to 0=1-4/((x+1)^2) is x=1,x=-3

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0=1-4/((x+1)^2)

0 = 1 - \frac{4}{( x + 1 ) ^{2}}

x = 1, x = - 3

Solution steps

0 = 1 - \frac{4}{( x + 1 ) ^{2}}

Move

1

to the left side

- 1 = - \frac{4}{( x + 1 ) ^{2}}

Multiply both sides by

(x + 1)^{2}

- (x + 1)^{2} = - 4

Solve

- (x + 1)^{2} = - 4 : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 1, x = - 3

1339 = \frac{152}{x}

\frac{x}{x - 8} + 6 = \frac{8}{x - 8}

36 x - 65 = \frac{36}{x}

\frac{x}{3} - \frac{x}{2 - x} = - 1

\frac{21}{- 4 h} = \frac{14}{11 + h}

What is the answer to 0=1-4/((x+1)^2) ?
The answer to 0=1-4/((x+1)^2) is x=1,x=-3
Solve for x: 0=1-4/((x+1)^2)
The solution is x=1,x=-3