What is the answer to ((t^2+t^2))/(t-1)=-100 ?

The answer to ((t^2+t^2))/(t-1)=-100 is t=5(3sqrt(3)-5),t=-5(5+3sqrt(3))

Solve for t: ((t^2+t^2))/(t-1)=-100

The solution is t=5(3sqrt(3)-5),t=-5(5+3sqrt(3))

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\frac{( t ^{2} + t ^{2} )}{t - 1} = - 100

t = 5 (33 - 5), t = - 5 (5 + 33)

Decimal Notation

t = 0.98076 \dots, t = - 50.98076 \dots

Solution steps

\frac{( t ^{2} + t ^{2} )}{t - 1} = - 100

Simplify

\frac{t ^{2} + t ^{2}}{t - 1} : \frac{2 t ^{2}}{t - 1}

\frac{2 t ^{2}}{t - 1} = - 100

Multiply both sides by

t - 1

2 t^{2} = - 100 (t - 1)

Solve

2 t^{2} = - 100 (t - 1) : t = 5 (33 - 5), t = - 5 (5 + 33)

t = 5 (33 - 5), t = - 5 (5 + 33)

Verify Solutions

Find undefined (singularity) points:

t = 1

Combine undefined points with solutions:

t = 5 (33 - 5), t = - 5 (5 + 33)

\frac{1}{( 1 - x ) ^{2}} = 0

\frac{39}{x + 17} = \frac{33}{5}

\frac{20}{30} = \frac{16}{a}

x, \frac{x y}{x + y} = 1

\frac{x ^{2} - 4}{x ^{2} - 9} = 0

What is the answer to ((t^2+t^2))/(t-1)=-100 ?
The answer to ((t^2+t^2))/(t-1)=-100 is t=5(3sqrt(3)-5),t=-5(5+3sqrt(3))
Solve for t: ((t^2+t^2))/(t-1)=-100
The solution is t=5(3sqrt(3)-5),t=-5(5+3sqrt(3))