What is the answer to 2z^2-(15)/(z^2)+7=0 ?

The answer to 2z^2-(15)/(z^2)+7=0 is z=sqrt(3/2),z=-sqrt(3/2),z=sqrt(5)i,z=-sqrt(5)i

Solve for z: 2z^2-(15)/(z^2)+7=0

The solution is z=sqrt(3/2),z=-sqrt(3/2),z=sqrt(5)i,z=-sqrt(5)i

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2 z^{2} - \frac{15}{z ^{2}} + 7 = 0

z = \frac{3}{2}, z = - \frac{3}{2}, z = 5 i, z = - 5 i

Solution steps

2 z^{2} - \frac{15}{z ^{2}} + 7 = 0

Multiply both sides by

z^{2}

2 z^{4} - 15 + 7 z^{2} = 0

Solve

2 z^{4} - 15 + 7 z^{2} = 0 : z = \frac{3}{2}, z = - \frac{3}{2}, z = 5 i, z = - 5 i

z = \frac{3}{2}, z = - \frac{3}{2}, z = 5 i, z = - 5 i

Verify Solutions

Find undefined (singularity) points:

z = 0

Combine undefined points with solutions:

z = \frac{3}{2}, z = - \frac{3}{2}, z = 5 i, z = - 5 i

a = \frac{x + 1}{x}

y, \frac{y + 2}{5 y - 1} = x

\frac{x - 1}{x - 3} = \frac{9}{5}

6 = x^{- 2}

\frac{9}{x} = \frac{3}{2 x} + 1

What is the answer to 2z^2-(15)/(z^2)+7=0 ?
The answer to 2z^2-(15)/(z^2)+7=0 is z=sqrt(3/2),z=-sqrt(3/2),z=sqrt(5)i,z=-sqrt(5)i
Solve for z: 2z^2-(15)/(z^2)+7=0
The solution is z=sqrt(3/2),z=-sqrt(3/2),z=sqrt(5)i,z=-sqrt(5)i