What is factor 25-(x^2+4x+4) ?

The solution to factor 25-(x^2+4x+4) is (7+x)(-x+3)

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factor 25-(x^2+4x+4)

factor

25 - (x^{2} + 4 x + 4)

(7 + x) (- x + 3)

Solution steps

25 - (x^{2} + 4 x + 4)

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

= 25 - (x + 2)^{2}

Factor the number:

25 = 5^{2}

= 5^{2} - (x + 2)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

5^{2} - (x + 2)^{2} = (5 + (x + 2)) (5 - (x + 2))

= (5 + (x + 2)) (5 - (x + 2))

Simplify

(5 + (x + 2)) (5 - (x + 2)) : (7 + x) (- x + 3)

= (7 + x) (- x + 3)

(x - 2)^{2} = 81

4 + 25

3 x^{2} = \frac{6}{7}

2 < \frac{∣ 6 - 2 x ∣}{3} < 4

- \frac{7}{8} + \frac{2}{3} - (- \frac{1}{4})

What is factor 25-(x^2+4x+4) ?
The solution to factor 25-(x^2+4x+4) is (7+x)(-x+3)