What is the answer to (-2x)/((x^2+1)^2)=0 ?

The answer to (-2x)/((x^2+1)^2)=0 is x=0

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(-2x)/((x^2+1)^2)=0

\frac{- 2 x}{( x ^{2} + 1 ) ^{2}} = 0

x = 0

Solution steps

\frac{- 2 x}{( x ^{2} + 1 ) ^{2}} = 0

Simplify

\frac{- 2 x}{( x ^{2} + 1 ) ^{2}} : - \frac{2 x}{( x ^{2} + 1 ) ^{2}}

- \frac{2 x}{( x ^{2} + 1 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x = 0

Divide both sides by

2

x = 0

\frac{6 x}{x + 4} = (x - 1)

x, \frac{49}{x} = 0.7

\frac{x - 6}{5 x} + 1 = \frac{x + 5}{x}

\frac{1}{26} = \frac{15000}{x}

- \frac{36000}{x ^{2}} + 10 = 0

What is the answer to (-2x)/((x^2+1)^2)=0 ?
The answer to (-2x)/((x^2+1)^2)=0 is x=0
Solve for x: (-2x)/((x^2+1)^2)=0
The solution is x=0