What are the solutions to the equation 3w^2=2-w ?

The solutions to the equation 3w^2=2-w are w= 2/3 ,w=-1

Find the zeros of 3w^2=2-w

The zeros of 3w^2=2-w are w= 2/3 ,w=-1

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3 w^{2} = 2 - w

w = \frac{2}{3}, w = - 1

Solution steps

3 w^{2} = 2 - w

Move

w

to the left side

3 w^{2} + w = 2

Move

2

to the left side

3 w^{2} + w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

w_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 1 + 5}{2 \cdot 3}, w_{2} = \frac{- 1 - 5}{2 \cdot 3}

w = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

w = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

w = \frac{2}{3}, w = - 1

3 (x - 2) < 18

- 56 = 7 (x - 3)

2 (x + 4) = 16

2 t^{2} + 7 t + 3

What are the solutions to the equation 3w^2=2-w ?
The solutions to the equation 3w^2=2-w are w= 2/3 ,w=-1
Find the zeros of 3w^2=2-w
The zeros of 3w^2=2-w are w= 2/3 ,w=-1