What is the answer to solvefor y,x= 1/(1+y^2) ?

The answer to solvefor y,x= 1/(1+y^2) is y=sqrt(1/x-1),y=-sqrt(1/x-1);\quad x\ne 0

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solvefor y,x= 1/(1+y^2)

solve for

y, x = \frac{1}{1 + y ^{2}}

y = \frac{1}{x} - 1, y = - \frac{1}{x} - 1; x \neq = 0

Solution steps

x = \frac{1}{1 + y ^{2}}

Multiply both sides by

1 + y^{2}

x (1 + y^{2}) = 1

Solve

x (1 + y^{2}) = 1 : y = \frac{1}{x} - 1, y = - \frac{1}{x} - 1; x \neq = 0

y = \frac{1}{x} - 1, y = - \frac{1}{x} - 1; x \neq = 0

\frac{4}{3 x + 1} = \frac{x}{2 x + 10}

\frac{1}{x ^{4}} = x^{- 4}

\frac{5 x + 5}{7 x + 7} = \frac{5}{7}

\frac{x - 6}{4 x} + 1 = \frac{x + 4}{x}

\frac{9}{y} = \frac{3}{7}

What is the answer to solvefor y,x= 1/(1+y^2) ?
The answer to solvefor y,x= 1/(1+y^2) is y=sqrt(1/x-1),y=-sqrt(1/x-1);\quad x\ne 0