What is the answer to (2x+x^2)/((1+x)^2)=0 ?

The answer to (2x+x^2)/((1+x)^2)=0 is x=0,x=-2

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(2x+x^2)/((1+x)^2)=0

\frac{2 x + x ^{2}}{( 1 + x ) ^{2}} = 0

x = 0, x = - 2

Solution steps

\frac{2 x + x ^{2}}{( 1 + x ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

2 x + x^{2} = 0

Solve

2 x + x^{2} = 0 : x = 0, x = - 2

x = 0, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 0, x = - 2

\frac{9}{x - 8} = \frac{8}{3}

\frac{24}{x} = 9

\frac{2}{x} = 5 - x

r + \frac{2}{r} = - 3

6 z - \frac{4}{1 + 2 z ^{-}} = 3

What is the answer to (2x+x^2)/((1+x)^2)=0 ?
The answer to (2x+x^2)/((1+x)^2)=0 is x=0,x=-2
Solve for x: (2x+x^2)/((1+x)^2)=0
The solution is x=0,x=-2