What is (16m^{-5}n^4)/(12m^2n^{-3)} ?

The solution to (16m^{-5}n^4)/(12m^2n^{-3)} is (4n^7)/(3m^7)

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simplify (16m^{-5}n^4)/(12m^2n^{-3)}

simplify

\frac{16 m ^{- 5} n ^{4}}{12 m ^{2} n ^{- 3}}

\frac{4 n ^{7}}{3 m ^{7}}

Solution steps

\frac{16 m ^{- 5} n ^{4}}{12 m ^{2} n ^{- 3}}

Factor the number:

16 = 4 \cdot 4

= \frac{4 \cdot 4 m ^{- 5} n ^{4}}{12 m ^{2} n ^{- 3}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 4 m ^{- 5} n ^{4}}{4 \cdot 3 m ^{2} n ^{- 3}}

Cancel the common factor:

4

= \frac{4 m ^{- 5} n ^{4}}{3 m ^{2} n ^{- 3}}

Simplify

\frac{n ^{4}}{n ^{- 3}} : n^{7}

= \frac{4 m ^{- 5} n ^{7}}{3 m ^{2}}

Simplify

\frac{m ^{- 5}}{m ^{2}} : \frac{1}{m ^{7}}

= \frac{4 n ^{7}}{3 m ^{7}}

r - 14 \geq 17

\frac{( 1 + i )}{( 1 - i )}

\frac{( 3 ab ) ^{3}}{2 a b ^{2} ( 6 a ) ^{2}}

\frac{1}{5} (3 x + 2) - \frac{1}{3} (x + 4) = 6

What is (16m^{-5}n^4)/(12m^2n^{-3)} ?
The solution to (16m^{-5}n^4)/(12m^2n^{-3)} is (4n^7)/(3m^7)