What is the answer to 4/(3-x)+1/(1-x)=0 ?

The answer to 4/(3-x)+1/(1-x)=0 is x= 7/5

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4/(3-x)+1/(1-x)=0

\frac{4}{3 - x} + \frac{1}{1 - x} = 0

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

\frac{4}{3 - x} + \frac{1}{1 - x} = 0

Multiply by LCM

4 (- x + 1) - x + 3 = 0

Move

3

to the right side

4 (- x + 1) - x = - 3

Expand

4 (- x + 1) - x : - 5 x + 4

- 5 x + 4 = - 3

Move

4

to the right side

- 5 x = - 7

Divide both sides by

- 5

x = \frac{7}{5}

Verify Solutions

Find undefined (singularity) points:

x = 3, x = 1

Combine undefined points with solutions:

x = \frac{7}{5}

\frac{6 x ^{2} + 12}{3 x - 4} = 2 x

\frac{x - 1}{x - 3} = 0

\frac{20}{x - 1} = 2 x + 3

\frac{r}{2} - 1 = \frac{4}{r}

\frac{x + 2}{8} = \frac{9}{x + 8}

What is the answer to 4/(3-x)+1/(1-x)=0 ?
The answer to 4/(3-x)+1/(1-x)=0 is x= 7/5
Solve for x: 4/(3-x)+1/(1-x)=0
The solution is x= 7/5