What are the solutions to the equation -2x^2+8x+6=0 ?

The solutions to the equation -2x^2+8x+6=0 are x=2-sqrt(7),x=2+sqrt(7)

Find the zeros of -2x^2+8x+6=0

The zeros of -2x^2+8x+6=0 are x=2-sqrt(7),x=2+sqrt(7)

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- 2 x^{2} + 8 x + 6 = 0

x = 2 - 7, x = 2 + 7

Decimal Notation

x = - 0.64575 \dots, x = 4.64575 \dots

Solution steps

- 2 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 6 = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 ( - 2 )}, x_{2} = \frac{- 8 - 4 7}{2 ( - 2 )}

x = \frac{- 8 + 4 7}{2 ( - 2 )} : 2 - 7

x = \frac{- 8 - 4 7}{2 ( - 2 )} : 2 + 7

The solutions to the quadratic equation are:

x = 2 - 7, x = 2 + 7

p^{2} + 12 p = - 5

2304

n^{2} + 5 n + 6

\frac{y ^{7}}{y ^{4}}

uv \cdot 4 u v^{5}

What are the solutions to the equation -2x^2+8x+6=0 ?
The solutions to the equation -2x^2+8x+6=0 are x=2-sqrt(7),x=2+sqrt(7)
Find the zeros of -2x^2+8x+6=0
The zeros of -2x^2+8x+6=0 are x=2-sqrt(7),x=2+sqrt(7)