What is the answer to (x-3)/2-(2x)/(x+2)=0 ?

The answer to (x-3)/2-(2x)/(x+2)=0 is x=6,x=-1

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(x-3)/2-(2x)/(x+2)=0

\frac{x - 3}{2} - \frac{2 x}{x + 2} = 0

x = 6, x = - 1

Solution steps

\frac{x - 3}{2} - \frac{2 x}{x + 2} = 0

Multiply by LCM

(x - 3) (x + 2) - 4 x = 0

Solve

(x - 3) (x + 2) - 4 x = 0 : x = 6, x = - 1

x = 6, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = 6, x = - 1

\frac{1}{x} = 1 - \frac{1}{4} x

0 = \frac{- 6}{x - 6}

\frac{7}{9} = \frac{13}{h - 16}

\frac{4}{3 x} = \frac{5}{5 x}

E, L = \frac{50 M}{E}

What is the answer to (x-3)/2-(2x)/(x+2)=0 ?
The answer to (x-3)/2-(2x)/(x+2)=0 is x=6,x=-1
Solve for x: (x-3)/2-(2x)/(x+2)=0
The solution is x=6,x=-1