What is the answer to (3^2-x)/(27-x)=0 ?

The answer to (3^2-x)/(27-x)=0 is x=9

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(3^2-x)/(27-x)=0

\frac{3 ^{2} - x}{27 - x} = 0

x = 9

Solution steps

\frac{3 ^{2} - x}{27 - x} = 0

Simplify

\frac{3 ^{2} - x}{27 - x} : \frac{9 - x}{27 - x}

\frac{9 - x}{27 - x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

9 - x = 0

Move

9

to the right side

- x = - 9

Divide both sides by

- 1

x = 9

Verify Solutions

Find undefined (singularity) points:

x = 27

Combine undefined points with solutions:

x = 9

\frac{1}{2 y} = 4

x + \frac{2}{x} = 6

\frac{- 3}{4 x ^{1}} = \frac{- 3}{4}

\frac{- 1}{a} = a (a)

\frac{5}{7 x} - \frac{2}{3 x} = 1