What is the answer to 1/(a^2)=a^{-2} ?

The answer to 1/(a^2)=a^{-2} is a\ne 0

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1/(a^2)=a^{-2}

\frac{1}{a ^{2}} = a^{- 2}

a \neq = 0

Solution steps

\frac{1}{a ^{2}} = a^{- 2}

Refine

\frac{1}{a ^{2}} = \frac{1}{a ^{2}}

Subtract

\frac{1}{a ^{2}}

from both sides

\frac{1}{a ^{2}} - \frac{1}{a ^{2}} = \frac{1}{a ^{2}} - \frac{1}{a ^{2}}

Simplify

0 = 0

Both sides are equal

True for all a

Verify Solutions

Find undefined (singularity) points:

a = 0

Since the equation is undefined for:

0

a \neq = 0

2 - \frac{32}{x ^{2}} = 0

\frac{10}{7} = \frac{n}{n - 7}

\frac{1}{2 x - 2 x ^{2}} = - 7

\frac{84}{d} = \frac{7}{2}

a = \frac{1}{2 ( b + b ) h}