What is the answer to (x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2 ?

The answer to (x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2 is x= 27/7

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(x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2

\frac{x - 3}{3} - \frac{3 ( x - 2 )}{2} = \frac{x - 3 - ( x + 2 )}{2}

x = \frac{27}{7}

Solution steps

\frac{x - 3}{3} - \frac{3 ( x - 2 )}{2} = \frac{x - 3 - ( x + 2 )}{2}

Multiply by LCM

2 (x - 3) - 9 (x - 2) = 3 (x - (x + 2) - 3)

Expand

2 (x - 3) - 9 (x - 2) : - 7 x + 12

Expand

3 (x - (x + 2) - 3) : - 15

- 7 x + 12 = - 15

Move

12

to the right side

- 7 x = - 27

Divide both sides by

- 7

x = \frac{27}{7}

8 y = 4

\frac{\frac{1}{x + h} - \frac{1}{x}}{h}

∣ m ∣ = 0

x^{2} + 7 x - a x - 7 a

x (x + 1) > 6

What is the answer to (x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2 ?
The answer to (x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2 is x= 27/7
Solve for x: (x-3)/3-(3(x-2))/2 =(x-3-(x+2))/2
The solution is x= 27/7