What is factor 2j^2+17j+8 ?

The solution to factor 2j^2+17j+8 is (2j+1)(j+8)

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factor 2j^2+17j+8

factor

2 j^{2} + 17 j + 8

(2 j + 1) (j + 8)

Solution steps

2 j^{2} + 17 j + 8

Break the expression into groups

= (2 j^{2} + j) + (16 j + 8)

Factor out

j

from

2 j^{2} + j : j (2 j + 1)

Factor out

8

from

16 j + 8 : 8 (2 j + 1)

= j (2 j + 1) + 8 (2 j + 1)

Factor out common term

2 j + 1

= (2 j + 1) (j + 8)

5 0^{\frac{3}{2}}

x^{3}

6 x + 8 = 9 x - 4

\frac{x ^{- 3}}{x ^{- 9}}

6 x^{2} + 40 x + 50 = 0