What is the answer to 7(3^x)=3(5^{5x-4}) ?

The answer to 7(3^x)=3(5^{5x-4}) is x=(ln(4375)-ln(3))/(5ln(5)-ln(3))

Solve for x: 7(3^x)=3(5^{5x-4})

The solution is x=(ln(4375)-ln(3))/(5ln(5)-ln(3))

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7 (3^{x}) = 3 (5^{5 x - 4})

x = \frac{ln ( 4375 ) - ln ( 3 )}{5 ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 1.04842 \dots

Solution steps

7 (3^{x}) = 3 (5^{5 x - 4})

Apply exponent rules

ln (7) + x ln (3) = ln (3) + (5 x - 4) ln (5)

Solve

ln (7) + x ln (3) = ln (3) + (5 x - 4) ln (5) : x = \frac{ln ( 4375 ) - ln ( 3 )}{5 ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 4375 ) - ln ( 3 )}{5 ln ( 5 ) - ln ( 3 )}

3 (4^{x}) = 5 (7^{2 x - 2})

6 (4^{x}) = 5 (3^{3 x - 5})

6 (4^{x}) = 5 (3^{2 x - 3})

e^{2 x} = 1

2 e^{x} = 3 e^{- x} + 5

What is the answer to 7(3^x)=3(5^{5x-4}) ?
The answer to 7(3^x)=3(5^{5x-4}) is x=(ln(4375)-ln(3))/(5ln(5)-ln(3))
Solve for x: 7(3^x)=3(5^{5x-4})
The solution is x=(ln(4375)-ln(3))/(5ln(5)-ln(3))