What is the answer to 3^{3x}=7^{2x+1} ?

The answer to 3^{3x}=7^{2x+1} is x=(ln(7))/(3ln(3)-2ln(7))

Solve for x: 3^{3x}=7^{2x+1}

The solution is x=(ln(7))/(3ln(3)-2ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{3 x} = 7^{2 x + 1}

x = \frac{ln ( 7 )}{3 ln ( 3 ) - 2 ln ( 7 )}

Decimal

x = - 3.26504 \dots

Solution steps

3^{3 x} = 7^{2 x + 1}

Apply exponent rules

3 x ln (3) = (2 x + 1) ln (7)

Solve

3 x ln (3) = (2 x + 1) ln (7) : x = \frac{ln ( 7 )}{3 ln ( 3 ) - 2 ln ( 7 )}

x = \frac{ln ( 7 )}{3 ln ( 3 ) - 2 ln ( 7 )}

4^{x} = 8

2^{1 - x^{2}} = \frac{1}{8}

e^{2 x} - e^{x} - 6 = 0

4^{x + 1} + 2^{x + 3} = 320

6^{x} + 4^{x} = 9^{x}

What is the answer to 3^{3x}=7^{2x+1} ?
The answer to 3^{3x}=7^{2x+1} is x=(ln(7))/(3ln(3)-2ln(7))
Solve for x: 3^{3x}=7^{2x+1}
The solution is x=(ln(7))/(3ln(3)-2ln(7))