What is the answer to 7^{x+2}=98 ?

The answer to 7^{x+2}=98 is x=(ln(98))/(ln(7))-2

Solve for x: 7^{x+2}=98

The solution is x=(ln(98))/(ln(7))-2

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7^{x + 2} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Decimal Notation

x = 0.35620 \dots

Solution steps

7^{x + 2} = 98

Apply exponent rules

(x + 2) ln (7) = ln (98)

Solve

(x + 2) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x, e^{a x} = C e^{b x}

5^{x} - 5^{5 - x} = 150

e^{5 - 3 x} = 10

y, x = e^{y}

5^{2 x} - 2 \cdot 5^{x} - 15 = 0

What is the answer to 7^{x+2}=98 ?
The answer to 7^{x+2}=98 is x=(ln(98))/(ln(7))-2
Solve for x: 7^{x+2}=98
The solution is x=(ln(98))/(ln(7))-2