What is the answer to 4^{1-x}=3^{2x+3} ?

The answer to 4^{1-x}=3^{2x+3} is x=-(3ln(3)-2ln(2))/(2ln(6))

Solve for x: 4^{1-x}=3^{2x+3}

The solution is x=-(3ln(3)-2ln(2))/(2ln(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{1 - x} = 3^{2 x + 3}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

Decimal Notation

x = - 0.53286 \dots

Solution steps

4^{1 - x} = 3^{2 x + 3}

Apply exponent rules

(1 - x) ln (4) = (2 x + 3) ln (3)

Solve

(1 - x) ln (4) = (2 x + 3) ln (3) : x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

x = - \frac{3 ln ( 3 ) - 2 ln ( 2 )}{2 ln ( 6 )}

ln (2 e^{x} + 1) = - 1

e^{2 x} - 4 = 0

2^{x + 1} + 5 \cdot 2^{x} = 28

2 7^{2 x} = 9^{x - 3}

e^{x} - 5 e^{- x} + 4 e^{- 3 x} = 0

What is the answer to 4^{1-x}=3^{2x+3} ?
The answer to 4^{1-x}=3^{2x+3} is x=-(3ln(3)-2ln(2))/(2ln(6))
Solve for x: 4^{1-x}=3^{2x+3}
The solution is x=-(3ln(3)-2ln(2))/(2ln(6))