What is the answer to 7^{x+1}-7^{x-1}=48 ?

The answer to 7^{x+1}-7^{x-1}=48 is x=1

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7^{x+1}-7^{x-1}=48

7^{x + 1} - 7^{x - 1} = 48

x = 1

Solution steps

7^{x + 1} - 7^{x - 1} = 48

Factor

7^{x + 1} - 7^{x - 1} : 48 \cdot 7^{x - 1}

48 \cdot 7^{x - 1} = 48

Divide both sides by

48

7^{x - 1} = 1

Apply exponent rules

(x - 1) ln (7) = ln (1)

Solve

(x - 1) ln (7) = ln (1) : x = 1

x = 1

e^{e^{x}} = 2

2^{x} = \frac{1}{4}

2^{x} = 6

8^{t} = 16

e^{2 x + 3} = 37

What is the answer to 7^{x+1}-7^{x-1}=48 ?
The answer to 7^{x+1}-7^{x-1}=48 is x=1
Solve for x: 7^{x+1}-7^{x-1}=48
The solution is x=1