What is the answer to 3^{2x+1}=(81)/(27^{x+2)} ?

The answer to 3^{2x+1}=(81)/(27^{x+2)} is x=-3/5

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3^{2x+1}=(81)/(27^{x+2)}

3^{2 x + 1} = \frac{81}{2 7 ^{x + 2}}

x = - \frac{3}{5}

Decimal Notation

x = - 0.6

Solution steps

3^{2 x + 1} = \frac{81}{2 7 ^{x + 2}}

Apply exponent rules

2 x + 1 = 3 (- x - 2) + 4

Solve

2 x + 1 = 3 (- x - 2) + 4 : x = - \frac{3}{5}

x = - \frac{3}{5}

Verify Solutions:

x = - \frac{3}{5}

True

The solution is

x = - \frac{3}{5}

(\frac{1}{9})^{x} = 2 7^{2 x + 4}

e^{x} = 8

3^{2 x + 2} + 3^{x + 2} = 4

5^{x} = 25

4^{x} = 5

What is the answer to 3^{2x+1}=(81)/(27^{x+2)} ?
The answer to 3^{2x+1}=(81)/(27^{x+2)} is x=-3/5
Solve for x: 3^{2x+1}=(81)/(27^{x+2)}
The solution is x=-3/5