What is the answer to 7^{x/2}=5^{1-x} ?

The answer to 7^{x/2}=5^{1-x} is x=(2ln(5))/(ln(175))

Solve for x: 7^{x/2}=5^{1-x}

The solution is x=(2ln(5))/(ln(175))

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7^{\frac{x}{2}} = 5^{1 - x}

x = \frac{2 ln ( 5 )}{ln ( 175 )}

Decimal Notation

x = 0.62323 \dots

Solution steps

7^{\frac{x}{2}} = 5^{1 - x}

Apply exponent rules

\frac{x}{2} ln (7) = (1 - x) ln (5)

Solve

\frac{x}{2} ln (7) = (1 - x) ln (5) : x = \frac{2 ln ( 5 )}{ln ( 175 )}

x = \frac{2 ln ( 5 )}{ln ( 175 )}

6 e^{- 4 k - 10} - 4 = 63

e^{x} - 1 = 0

2 5^{x} + 5^{3 - 2 x} = 30

3 (2^{x}) = 42

e^{6 x} - 5 e^{3 x} + 4 = 0

What is the answer to 7^{x/2}=5^{1-x} ?
The answer to 7^{x/2}=5^{1-x} is x=(2ln(5))/(ln(175))
Solve for x: 7^{x/2}=5^{1-x}
The solution is x=(2ln(5))/(ln(175))