What is the answer to 2^{x-1}=3^x ?

The answer to 2^{x-1}=3^x is x=(ln(2))/(ln(2)-ln(3))

Solve for x: 2^{x-1}=3^x

The solution is x=(ln(2))/(ln(2)-ln(3))

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2^{x - 1} = 3^{x}

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = - 1.70951 \dots

Solution steps

2^{x - 1} = 3^{x}

Apply exponent rules

(x - 1) ln (2) = x ln (3)

Solve

(x - 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 2 )}{ln ( 2 ) - ln ( 3 )}

2^{n} = 1000

4^{2 x + 3} = 1

9^{- 3 x} = (\frac{1}{27})^{x + 3}

1 0^{x} = 4

5^{x} + 5^{5 - x} = 150

What is the answer to 2^{x-1}=3^x ?
The answer to 2^{x-1}=3^x is x=(ln(2))/(ln(2)-ln(3))
Solve for x: 2^{x-1}=3^x
The solution is x=(ln(2))/(ln(2)-ln(3))