What is the answer to 3^x=7^{x+2} ?

The answer to 3^x=7^{x+2} is x=(2ln(7))/(ln(3)-ln(7))

Solve for x: 3^x=7^{x+2}

The solution is x=(2ln(7))/(ln(3)-ln(7))

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3^{x} = 7^{x + 2}

x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

Solution steps

3^{x} = 7^{x + 2}

Apply exponent rules

x ln (3) = (x + 2) ln (7)

Solve

x ln (3) = (x + 2) ln (7) : x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

2^{x - 3} + 2^{x - 1} + 2^{x} = 52

3 6^{x} + 4 2^{x} = 4 9^{x}

5 \cdot 1 8^{6 x} = 26

5^{x} = 4

6^{x} = 216

What is the answer to 3^x=7^{x+2} ?
The answer to 3^x=7^{x+2} is x=(2ln(7))/(ln(3)-ln(7))
Solve for x: 3^x=7^{x+2}
The solution is x=(2ln(7))/(ln(3)-ln(7))