What is the answer to (2/3)^x=5^{1-x} ?

The answer to (2/3)^x=5^{1-x} is x=(ln(5))/(ln(10/3))

Solve for x: (2/3)^x=5^{1-x}

The solution is x=(ln(5))/(ln(10/3))

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(\frac{2}{3})^{x} = 5^{1 - x}

x = \frac{ln ( 5 )}{ln ( \frac{10}{3} )}

Decimal Notation

x = 1.33677 \dots

Solution steps

(\frac{2}{3})^{x} = 5^{1 - x}

Apply exponent rules

x ln (\frac{2}{3}) = (1 - x) ln (5)

Solve

x ln (\frac{2}{3}) = (1 - x) ln (5) : x = \frac{ln ( 5 )}{ln ( \frac{10}{3} )}

x = \frac{ln ( 5 )}{ln ( \frac{10}{3} )}

3 e^{x} + 5 = 8

5 (7^{2 x - 1}) = 7 (5^{x + 2})

π^{1 - x} = e^{x}

4^{x} + 4^{- x} = \frac{5}{2}

2^{x} + 2^{1 - x} = 3

What is the answer to (2/3)^x=5^{1-x} ?
The answer to (2/3)^x=5^{1-x} is x=(ln(5))/(ln(10/3))
Solve for x: (2/3)^x=5^{1-x}
The solution is x=(ln(5))/(ln(10/3))