What is the answer to 16^{2x+1}=9^{3x-4} ?

The answer to 16^{2x+1}=9^{3x-4} is x=-(8ln(3)+4ln(2))/(2(-3ln(3)+4ln(2)))

Solve for x: 16^{2x+1}=9^{3x-4}

The solution is x=-(8ln(3)+4ln(2))/(2(-3ln(3)+4ln(2)))

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1 6^{2 x + 1} = 9^{3 x - 4}

x = - \frac{8 ln ( 3 ) + 4 ln ( 2 )}{2 ( - 3 ln ( 3 ) + 4 ln ( 2 ) )}

Decimal Notation

x = 11.04780 \dots

Solution steps

1 6^{2 x + 1} = 9^{3 x - 4}

Apply exponent rules

(2 x + 1) ln (16) = (3 x - 4) ln (9)

Solve

(2 x + 1) ln (16) = (3 x - 4) ln (9) : x = - \frac{8 ln ( 3 ) + 4 ln ( 2 )}{2 ( - 3 ln ( 3 ) + 4 ln ( 2 ) )}

x = - \frac{8 ln ( 3 ) + 4 ln ( 2 )}{2 ( - 3 ln ( 3 ) + 4 ln ( 2 ) )}

1 6^{2 x - 3} 4^{- 2 x} = 16

13 e^{x} = 2 \cdot 3^{- x}

1 0^{x} = 3

4^{y - 2} = \frac{1}{3 ^{- y}}

5 = 2^{x}

What is the answer to 16^{2x+1}=9^{3x-4} ?
The answer to 16^{2x+1}=9^{3x-4} is x=-(8ln(3)+4ln(2))/(2(-3ln(3)+4ln(2)))
Solve for x: 16^{2x+1}=9^{3x-4}
The solution is x=-(8ln(3)+4ln(2))/(2(-3ln(3)+4ln(2)))