What is the answer to 3^{x+2}=7 ?

The answer to 3^{x+2}=7 is x=(ln(7))/(ln(3))-2

Solve for x: 3^{x+2}=7

The solution is x=(ln(7))/(ln(3))-2

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3^{x + 2} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 2

Decimal Notation

x = - 0.22875 \dots

Solution steps

3^{x + 2} = 7

Apply exponent rules

(x + 2) ln (3) = ln (7)

Solve

(x + 2) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 2

x = \frac{ln ( 7 )}{ln ( 3 )} - 2

3^{x} = (\frac{1}{3})^{x + 1}

8 1^{x - 1} = 2 7^{x}

4^{x} - 3 \cdot 2^{x + 1} + 8 = 0

5^{3 - 2 x} = 5^{- x}

2^{5 x + 1} = 8 1^{x - 2}

What is the answer to 3^{x+2}=7 ?
The answer to 3^{x+2}=7 is x=(ln(7))/(ln(3))-2
Solve for x: 3^{x+2}=7
The solution is x=(ln(7))/(ln(3))-2