What is the answer to 2^{1-x}=3 ?

The answer to 2^{1-x}=3 is x=-(ln(3)-ln(2))/(ln(2))

Solve for x: 2^{1-x}=3

The solution is x=-(ln(3)-ln(2))/(ln(2))

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2^{1 - x} = 3

x = - \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

Solution steps

2^{1 - x} = 3

Apply exponent rules

(1 - x) ln (2) = ln (3)

Solve

(1 - x) ln (2) = ln (3) : x = - \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

x = - \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

3^{x} = 11

y, x = 2^{y}

x, y = b + a e^{- x}

e^{3 x} = 1

e^{3 x} = 5

What is the answer to 2^{1-x}=3 ?
The answer to 2^{1-x}=3 is x=-(ln(3)-ln(2))/(ln(2))
Solve for x: 2^{1-x}=3
The solution is x=-(ln(3)-ln(2))/(ln(2))