What are the solutions to the equation (8w-4)^2=0 ?

The solutions to the equation (8w-4)^2=0 are w= 1/2

Find the zeros of (8w-4)^2=0

The zeros of (8w-4)^2=0 are w= 1/2

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(8 w - 4)^{2} = 0

w = \frac{1}{2}

Solution steps

(8 w - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

8 w - 4 = 0 : w = \frac{1}{2}

The solution to the quadratic equation is:

w = \frac{1}{2}

x + 12 \leq - \frac{1}{3} or x + 12 \geq \frac{1}{3}

(3 x + 4) 2 = 9

5 (x + 3) + 9 = - 2 (x - 2) - 1

6 (x - \frac{1}{3}) = - 2 (x + 23)

\frac{1}{3} \cdot 12

What are the solutions to the equation (8w-4)^2=0 ?
The solutions to the equation (8w-4)^2=0 are w= 1/2
Find the zeros of (8w-4)^2=0
The zeros of (8w-4)^2=0 are w= 1/2