What is the answer to 3^x+3^{1-x}= 28/3 ?

The answer to 3^x+3^{1-x}= 28/3 is x=2,x=-1

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3^x+3^{1-x}= 28/3

3^{x} + 3^{1 - x} = \frac{28}{3}

x = 2, x = - 1

Solution steps

3^{x} + 3^{1 - x} = \frac{28}{3}

Apply exponent rules

3^{x} + (3^{x})^{- 1} \cdot 3^{1} = \frac{28}{3}

Rewrite the equation with

3^{x} = u

u + (u)^{- 1} \cdot 3^{1} = \frac{28}{3}

Solve

u + u^{- 1} \cdot 3^{1} = \frac{28}{3} : u = 9, u = \frac{1}{3}

u = 9, u = \frac{1}{3}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 9 : x = 2

Solve

3^{x} = \frac{1}{3} : x = - 1

x = 2, x = - 1

2^{x} = 3 - x

4^{x} = 256

x, 2 7^{x} = 9^{y}

3^{2 x - 1} = \frac{1}{27}

e^{- 0.2 x} = 4

What is the answer to 3^x+3^{1-x}= 28/3 ?
The answer to 3^x+3^{1-x}= 28/3 is x=2,x=-1
Solve for x: 3^x+3^{1-x}= 28/3
The solution is x=2,x=-1