What is the answer to 7^{3-x}=5^{x+1} ?

The answer to 7^{3-x}=5^{x+1} is x=(3ln(7)-ln(5))/(ln(35))

Solve for x: 7^{3-x}=5^{x+1}

The solution is x=(3ln(7)-ln(5))/(ln(35))

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7^{3 - x} = 5^{x + 1}

x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

Solution steps

7^{3 - x} = 5^{x + 1}

Apply exponent rules

(3 - x) ln (7) = (x + 1) ln (5)

Solve

(3 - x) ln (7) = (x + 1) ln (5) : x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

4^{x + 5} - 4^{x + 4} = 384

3^{1 - x^{2}} = \frac{1}{27}

e^{x} = - 2

2^{x} - 1 = x + 2

x e^{2 x} = 0

What is the answer to 7^{3-x}=5^{x+1} ?
The answer to 7^{3-x}=5^{x+1} is x=(3ln(7)-ln(5))/(ln(35))
Solve for x: 7^{3-x}=5^{x+1}
The solution is x=(3ln(7)-ln(5))/(ln(35))