What is the answer to 3^{1-2x}=4^x ?

The answer to 3^{1-2x}=4^x is x=(ln(3))/(2ln(6))

Solve for x: 3^{1-2x}=4^x

The solution is x=(ln(3))/(2ln(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{1 - 2 x} = 4^{x}

x = \frac{ln ( 3 )}{2 ln ( 6 )}

Solution steps

3^{1 - 2 x} = 4^{x}

Apply exponent rules

(1 - 2 x) ln (3) = x ln (4)

Solve

(1 - 2 x) ln (3) = x ln (4) : x = \frac{ln ( 3 )}{2 ln ( 6 )}

x = \frac{ln ( 3 )}{2 ln ( 6 )}

5^{x} = 17

2^{x + 5} = 9

2 7^{x} = 81

3^{x + 1} = \frac{1}{81}

7.5 6^{X} = 6.76

What is the answer to 3^{1-2x}=4^x ?
The answer to 3^{1-2x}=4^x is x=(ln(3))/(2ln(6))
Solve for x: 3^{1-2x}=4^x
The solution is x=(ln(3))/(2ln(6))