What is the answer to 8^{2x+1}=16^{2x-3} ?

The answer to 8^{2x+1}=16^{2x-3} is x= 15/2

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8^{2x+1}=16^{2x-3}

8^{2 x + 1} = 1 6^{2 x - 3}

x = \frac{15}{2}

Decimal Notation

x = 7.5

Solution steps

8^{2 x + 1} = 1 6^{2 x - 3}

Apply exponent rules

3 (2 x + 1) = 4 (2 x - 3)

Solve

3 (2 x + 1) = 4 (2 x - 3) : x = \frac{15}{2}

x = \frac{15}{2}

3^{x} = \frac{1}{3}

200 = 100 e^{r (6)}

3^{3 x - 4} = 15

5 6^{3 x - 8} = 1

e^{2 x + 3} - 7 = 0

What is the answer to 8^{2x+1}=16^{2x-3} ?
The answer to 8^{2x+1}=16^{2x-3} is x= 15/2
Solve for x: 8^{2x+1}=16^{2x-3}
The solution is x= 15/2