What is the answer to 4^{x+4}-4^{x+3}=96 ?

The answer to 4^{x+4}-4^{x+3}=96 is x=-1/2

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4^{x+4}-4^{x+3}=96

4^{x + 4} - 4^{x + 3} = 96

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4^{x + 4} - 4^{x + 3} = 96

Factor

4^{x + 4} - 4^{x + 3} : 3 \cdot 4^{x + 3}

3 \cdot 4^{x + 3} = 96

Divide both sides by

3

4^{x + 3} = 32

Apply exponent rules

2 (x + 3) = 5

Solve

2 (x + 3) = 5 : x = - \frac{1}{2}

x = - \frac{1}{2}

e^{x} + 5 e^{- x} = 6

2^{x} = 14

6 - 5^{x} = 5^{1 - x}

(\frac{9}{8})^{3 x + 12} = 1

3^{2 x} - 4 \cdot 3^{x} + 3 = 0

What is the answer to 4^{x+4}-4^{x+3}=96 ?
The answer to 4^{x+4}-4^{x+3}=96 is x=-1/2
Solve for x: 4^{x+4}-4^{x+3}=96
The solution is x=-1/2