What is the answer to 2^{x+1}+2^{x-1}=10 ?

The answer to 2^{x+1}+2^{x-1}=10 is x=2

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2^{x+1}+2^{x-1}=10

2^{x + 1} + 2^{x - 1} = 10

x = 2

Solution steps

2^{x + 1} + 2^{x - 1} = 10

Factor

2^{x + 1} + 2^{x - 1} : 5 \cdot 2^{x - 1}

5 \cdot 2^{x - 1} = 10

Divide both sides by

5

2^{x - 1} = 2

Apply exponent rules

x - 1 = 1

Solve

x - 1 = 1 : x = 2

x = 2

e^{2 x} - 2 e^{x} + 1 = 0

5^{x + 1} + 5^{x} + 5^{x - 1} = 775

e^{2 x} = 3

8^{x} = 2

t, A = P e^{r t}

What is the answer to 2^{x+1}+2^{x-1}=10 ?
The answer to 2^{x+1}+2^{x-1}=10 is x=2
Solve for x: 2^{x+1}+2^{x-1}=10
The solution is x=2