What is the answer to 5^{2x}-30(5^x)+125=0 ?

The answer to 5^{2x}-30(5^x)+125=0 is x=2,x=1

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5^{2x}-30(5^x)+125=0

5^{2 x} - 30 (5^{x}) + 125 = 0

x = 2, x = 1

Solution steps

5^{2 x} - 30 (5^{x}) + 125 = 0

Apply exponent rules

(5^{x})^{2} - 30 \cdot 5^{x} + 125 = 0

Rewrite the equation with

5^{x} = u

(u)^{2} - 30 u + 125 = 0

Solve

u^{2} - 30 u + 125 = 0 : u = 25, u = 5

u = 25, u = 5

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 25 : x = 2

Solve

5^{x} = 5 : x = 1

x = 2, x = 1

e^{2 x} - 5 = 0

2 6^{9 x + 5} = 1

(\frac{1}{3})^{x - 1} = 27

x, y^{3 x} = n + 1

3^{5 x - 4} = 9^{2 x - 3}

What is the answer to 5^{2x}-30(5^x)+125=0 ?
The answer to 5^{2x}-30(5^x)+125=0 is x=2,x=1
Solve for x: 5^{2x}-30(5^x)+125=0
The solution is x=2,x=1