What is the answer to 4^{x+4}=5^{2x+5} ?

The answer to 4^{x+4}=5^{2x+5} is x=(5ln(5)-8ln(2))/(2(ln(2)-ln(5)))

Solve for x: 4^{x+4}=5^{2x+5}

The solution is x=(5ln(5)-8ln(2))/(2(ln(2)-ln(5)))

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4^{x + 4} = 5^{2 x + 5}

x = \frac{5 ln ( 5 ) - 8 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

Decimal Notation

x = - 1.36529 \dots

Solution steps

4^{x + 4} = 5^{2 x + 5}

Apply exponent rules

(x + 4) ln (4) = (2 x + 5) ln (5)

Solve

(x + 4) ln (4) = (2 x + 5) ln (5) : x = \frac{5 ln ( 5 ) - 8 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

x = \frac{5 ln ( 5 ) - 8 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

4 e^{2 x} = 12

\frac{10}{1 + e ^{- x}} = 2

12 5^{x + 2} = 62 5^{x + 6}

2^{3 x} = 8^{1 - x}

3 x + 3 = e^{x}

What is the answer to 4^{x+4}=5^{2x+5} ?
The answer to 4^{x+4}=5^{2x+5} is x=(5ln(5)-8ln(2))/(2(ln(2)-ln(5)))
Solve for x: 4^{x+4}=5^{2x+5}
The solution is x=(5ln(5)-8ln(2))/(2(ln(2)-ln(5)))