What is the answer to (27)/(3^{1-3n)}=9 ?

The answer to (27)/(3^{1-3n)}=9 is n=0

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(27)/(3^{1-3n)}=9

\frac{27}{3 ^{1 - 3 n}} = 9

n = 0

Solution steps

\frac{27}{3 ^{1 - 3 n}} = 9

Apply exponent rules

- 1 + 3 n = - 1

Solve

- 1 + 3 n = - 1 : n = 0

n = 0

Verify Solutions:

n = 0

True

The solution is

n = 0

4^{x + 1} + 4^{x} = 20

3^{3 x + 5} = 9^{2 x + 1}

3 x^{2} e^{3 x} + 2 x e^{3 x} = 0

2^{2 x} - 10 (2^{x}) + 16 = 0

e^{x} + e^{- x} = 4

What is the answer to (27)/(3^{1-3n)}=9 ?
The answer to (27)/(3^{1-3n)}=9 is n=0
Solve for n: (27)/(3^{1-3n)}=9
The solution is n=0