What is the answer to 64*16^{-3x}=16^{3x-2} ?

The answer to 64*16^{-3x}=16^{3x-2} is x= 7/12

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64*16^{-3x}=16^{3x-2}

64 \cdot 1 6^{- 3 x} = 1 6^{3 x - 2}

x = \frac{7}{12}

Solution steps

64 \cdot 1 6^{- 3 x} = 1 6^{3 x - 2}

Apply exponent rules

ln (64) - 3 x ln (16) = (3 x - 2) ln (16)

Solve

ln (64) - 3 x ln (16) = (3 x - 2) ln (16) : x = \frac{7}{12}

x = \frac{7}{12}

12 5^{2 - 3 x} = 5

3^{x} = 27

3^{x} + 3^{(3 - x)} = 12

8^{- x} = \frac{1}{2}

7^{x} = \frac{1}{49}

What is the answer to 64*16^{-3x}=16^{3x-2} ?
The answer to 64*16^{-3x}=16^{3x-2} is x= 7/12
Solve for x: 64*16^{-3x}=16^{3x-2}
The solution is x= 7/12