What is the answer to solvefor n,f=p(1+i)^n ?

The answer to solvefor n,f=p(1+i)^n is n=(ln(f/p))/(ln(1+i))

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solvefor n,f=p(1+i)^n

solve for

n, f = p (1 + i)^{n}

n = \frac{ln ( \frac{f}{p} )}{ln ( 1 + i )}

Solution steps

f = p (1 + i)^{n}

Switch sides

p (1 + i)^{n} = f

Divide both sides by

p

(1 + i)^{n} = \frac{f}{p}

Apply exponent rules

n ln (1 + i) = ln (\frac{f}{p})

Solve

n ln (1 + i) = ln (\frac{f}{p}) : n = \frac{ln ( \frac{f}{p} )}{ln ( 1 + i )}

n = \frac{ln ( \frac{f}{p} )}{ln ( 1 + i )}

9^{x - 2} = 3^{3 x + 1}

2^{24} = (2^{y})^{3}

9^{x} = 15

e^{2 x} - 2 e^{x} - 3 = 0

2^{a} = 8

What is the answer to solvefor n,f=p(1+i)^n ?
The answer to solvefor n,f=p(1+i)^n is n=(ln(f/p))/(ln(1+i))