What is the answer to 3^x+3^x=27 ?

The answer to 3^x+3^x=27 is x=(ln(27/2))/(ln(3))

Solve for x: 3^x+3^x=27

The solution is x=(ln(27/2))/(ln(3))

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3^{x} + 3^{x} = 27

x = \frac{ln ( \frac{27}{2} )}{ln ( 3 )}

Solution steps

3^{x} + 3^{x} = 27

Add similar elements:

3^{x} + 3^{x} = 2 \cdot 3^{x}

2 \cdot 3^{x} = 27

Divide both sides by

2

3^{x} = \frac{27}{2}

Apply exponent rules

x ln (3) = ln (\frac{27}{2})

Solve

x ln (3) = ln (\frac{27}{2}) : x = \frac{ln ( \frac{27}{2} )}{ln ( 3 )}

x = \frac{ln ( \frac{27}{2} )}{ln ( 3 )}

e^{- x} = 5

ln (e^{x}) = 4

6 4^{- 2 x + 3} = 1

(2^{4})^{2} = 2^{n}

7^{2 x} = 2 (5^{3 x + 1})

What is the answer to 3^x+3^x=27 ?
The answer to 3^x+3^x=27 is x=(ln(27/2))/(ln(3))
Solve for x: 3^x+3^x=27
The solution is x=(ln(27/2))/(ln(3))