What is the answer to 9^x=(1/27)^{x-2} ?

The answer to 9^x=(1/27)^{x-2} is x= 6/5

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9^x=(1/27)^{x-2}

9^{x} = (\frac{1}{27})^{x - 2}

x = \frac{6}{5}

Solution steps

9^{x} = (\frac{1}{27})^{x - 2}

Apply exponent rules

2 x = - 3 (x - 2)

Solve

2 x = - 3 (x - 2) : x = \frac{6}{5}

x = \frac{6}{5}

9^{x + 1} = 2 7^{3 x - 4}

e^{2 x} - 10 e^{x} + 9 = 0

5^{2 x} = 2 5^{4 - x}

2 e^{x} = 110

2^{x} = 1024

What is the answer to 9^x=(1/27)^{x-2} ?
The answer to 9^x=(1/27)^{x-2} is x= 6/5
Solve for x: 9^x=(1/27)^{x-2}
The solution is x= 6/5